Fredy decided to go on a long drive with his girl friend on a deserted highway to discuss about his marriage with a condition that, if she solves the puzzle – Fredy will marry her, otherwise he will say bye to her on the highway. Fredy asked his girl friend, on this deserted highway, the probability of observing a car during a thirty-minute period is 95 percent. What is the chance of observing a car in ten-minute period? Please help her to marry Fredy!
Loratis Career School
Log True North!
Twit With Us
Tweets by loratisFind Me!
-
Join 28 other subscribers
Find Your Date-Month-Year!
May 2024 M T W T F S S 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 True North+
(function() {
var po = document.createElement('script'); po.type = 'text/javascript'; po.async = true;
po.src = 'https://apis.google.com/js/plusone.js';
var s = document.getElementsByTagName('script')[0]; s.parentNode.insertBefore(po, s);
})();
Unknown Feed- An error has occurred; the feed is probably down. Try again later.
Feed Us
Loratis True Visit Stats
- 70,880 hits
SetMyCareer 
can i get the soln?
Solution will be posted tomorrow evening. Please try solving it.
31.6 %
Rahul, you have missed one assumption while solving perhaps you got the different answer
approximate 32 %
its 63.1 %
Good One! Please give us the steps!
Let p be the probability of seeing a car in 10
Then probability of not seeing a car is
1-p
so (1-p)^3=0.05
so p=0.631.
Let p is a probability to see a car in 10 minutes.
Then (1-p) is probability NOT to see a car in 10 minutes.
Then probability NOT to see a car in 30 minutes is (1-p)*(1-p)*(1-p).
(1-p)^3 == 0.05
So p = 1-0.05^(1/3)~ 0.63
Thanks Rishabh for the steps! Good one!
ur welcome sir!!!
63.1%
63.1% sir